By William Ma
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5 Steps to a five: AP Calculus BC good points an efficient, 5-step plan to lead your coaching application and assist you construct the talents, wisdom, and test-taking self assurance you want to prevail. This absolutely revised variation covers the most recent path syllabus and offers version checks that mirror the most recent model of the exam.
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Read or Download AP Calculus BC, 2014-2015 Edition PDF
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Extra info for AP Calculus BC, 2014-2015 Edition
12. See Figure DS-3. The graph of f is concave upward for x < x2. f' incr. decr. – [ b 0 incr. decr. rel. max. Figure DS-5 15. See Figure DS-6. A change of concavity occurs at x = 0 for q . Thus, q has a point of inflection at x = 0. None of the other functions has a point of inflection. q' incr [ a x2 f" + – q" f Concave upward Concave downward q Figure DS-3 0 decr [ b 0 + Concave upward – Concave downward Figure DS-6 30 STEP 2. Determine Your Test Readiness 16. Solve x = 1 + e −t for t. x − 1 = e −t ⇒ − ln (x − 1) = t.
G is continuous on (a , b). III. g >0 on (a , b). 4. If f (x ) = |2x e x |, what is the value of lim+ f (x )? y x →0 Chapter 6 g 5. If f (x ) = −2 csc (5x ), find f π . 6 6. Given the equation y = (x + 1)(x − 3)2 , what is the instantaneous rate of change of y at x = −1? tan 7. What is lim ∆x →0 π + ∆x 4 ∆x − tan π 4 ? a 0 Figure D-2 b x 22 STEP 2. Determine Your Test Readiness 11. The graph of f is shown in Figure D-3 and f is twice differentiable, which of the following statements is true? y x 14.
81 . 325. Take a Diagnostic Exam d y −y and y = 3 and x = 2, approximate = dx x2 y when x = 3. 5. −3 dy y (2) = 3 and = so d x x = 2, y = 3 4 56. 415. Chapter 14 57. The series n=0 3 is a series with positive (n + 1)4 terms, which can be compared to the series ∞ n=0 3 . n4 ∞ n=0 3 =3 n4 ∞ n=0 1 and n4 ∞ n=0 1 is a n4 p-series with p = 4, and therefore convergent. ∞ 3 is term by term smaller than (n + 1)4 n=0 ∞ n=0 3 and so n4 ∞ n=0 3 converges. (n + 1)4 x2 x3 x4 + − + ··· 2 3 4 is an alternating series with general term (−1)n − 1 x n .